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31076a4f33
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| bdb74646a2 |
Vendored
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@@ -0,0 +1,35 @@
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[[Force and Translational Dynamics]]
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Spring force uses Hooke's law: $$\vec F_s=-k\Delta \vec x$$
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$k$ = stiffness of spring
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$\Delta x$ = displacement from measured from a relaxed length
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negative sign means force points back towards equilibrium
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Vertical spring stretched the spring until $k\Delta x = mg$ at equilibrium.
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Hooke's law in magnitude is $|\vec F_s|=k|\Delta x|$
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Spring constant k measures in N/m. Bigger k means more stiff (obviously).
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Spring force is a restoring force that points towards equilibrium position of object spring relationship.
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For a vertical spring with hanging mass, relaxed length is not equilibrium because gravity stretches spring
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## Ideal Spring:
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The mass of an ideal spring is treated as negligible compared to the objects attached to it.
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- You can ignore the spring's own weight in calculations.
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- You focus only on the interaction between the spring and the attached object.
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An ideal spring follows a linear force-displacement relationship.
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- The force is directly proportional to how far the spring is stretched or compressed.
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- Stretch it twice as far and it pulls back with twice the force.
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- This behavior stays consistent each time you use the spring.
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## Direction of Spring Force
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When a string is stretched:
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* $\Delta x$ is positive
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* Spring force is negative, pulling back
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When a string is compressed:
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* $\Delta x$ is negative
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* Spring force is positive, pushing forward
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WHEN CALCULATING THE $\Delta x$ OF A VERTICAL SPRING WITH A HANGING MASS, USE THE RELAXED POSITION NOT THE EQUILIBRIUM POSITION.
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@@ -0,0 +1,16 @@
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[[Work Energy and Power]]
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Formula is: $$K=\frac{1}{2}mv^2$$
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$K$ in joules
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$m$ in kg
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$v$ in m/s
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* Kinetic energy is scalar, only magnitude and never negative.
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* Because velocity is squared, changing speed affects energy more than changing mass.
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* For a system of objects, total kinetic energy is the sum of each object's kinetic energy.
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* Different observers in different reference frames can calculate different kinetic energies.
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If a dude standing on earth sees a 1kg ball travelling at 10m/s, he'll calculate it as 50J. If a dude taped to the ball calculates it he'll calculate 0J. If a theoretical god looked at it from a universal standpoint he'd probably calculate like $1*10^6$ Joules due to Earth orbiting the sun and the solar system orbiting the Milky Way.
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In a collision, total energy before and after is consistent in the observers frame.
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@@ -0,0 +1,3 @@
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[[physics]]
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WEaP
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